The Kraus inequality for multivalent functions


如何引用文章

全文:

开放存取 开放存取
受限制的访问 ##reader.subscriptionAccessGranted##
受限制的访问 订阅存取

详细

For a holomorphic function f, f′(0) ≠ 0, in the unit disk U, we establish a geometric constraint on the image f(U) for which the classical Kraus inequality |Sf (0)| ≤ 6 holds; earlier, it was known only in the case of the conformal mapping of f. Here Sf (0) is the Schwarzian derivative of the function f calculated at the point z = 0. The proof is based on the strengthened version of Lavrent’ev’s theorem on the extremal decomposition of the Riemann sphere into two disjoint domains.

作者简介

V. Dubinin

Far-Eastern Federal University; Institute of Applied Mathematics, Far-Eastern Branch

编辑信件的主要联系方式.
Email: dubinin@iam.dvo.ru
俄罗斯联邦, Vladivostok; Vladivostok

补充文件

附件文件
动作
1. JATS XML

版权所有 © Pleiades Publishing, Ltd., 2017